#L0008. 3N+1 判断奇偶数
3N+1 判断奇偶数
1. Description
Take an integer input and assign the value to variable num
- if
numis odd,assign3 * num + 1tonum - if
numis even,assignnumdivided by2tonum
2. Input & Output
Input:
- Use
input()as input. Notice that the value you get frominput()is a string - Refering code below to load multiple inputs
s = input().split(" ")
# 读取第一个输入,如果想要读入整数,就通过 int() 把它变成整数
input_1 = int(s[0])
# 读取第二个输入,不需要数字时,就保留字符串
input_2 = s[1]
Output:
- Use
print()for your output
Example
# Input:
15
# Output:
46
# Input:
200
# Output:
100